F(-2)=3x^2-5x+1

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Solution for F(-2)=3x^2-5x+1 equation: 



(-2)=3F^2-5F+1

We move all terms to the left:

(-2)-(3F^2-5F+1)=0

We add all the numbers together, and all the variables

-(3F^2-5F+1)-2=0

We get rid of parentheses

-3F^2+5F-1-2=0

We add all the numbers together, and all the variables

-3F^2+5F-3=0

a = -3; b = 5; c = -3;
Δ = b2-4ac
Δ = 52-4·(-3)·(-3)
Δ = -11
Delta is less than zero, so there is no solution for the equation

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